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d3.cpp
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141 lines (129 loc) · 2.9 KB
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#include <vector>
#include <iostream>
#include <climits>
using namespace std;
// First negative number in window of size K
vector<int> answer1(const vector<int> arr, int K)
{
int n = arr.size();
vector<int> negatives;
vector<int> result;
for (int i = 0; i < K; i++)
{
if (arr[i] < 0)
{
negatives.push_back(arr[i]);
}
}
for (int i = K; i < n; i++)
{
if (negatives.size() == 0)
{
result.push_back(0);
}
else
{
result.push_back(negatives.front());
}
if (arr[i] < 0)
{
negatives.push_back(arr[i]);
}
if (arr[i - K] < 0)
{
negatives.erase(negatives.begin());
}
}
return result;
}
// revision of answer on day4
vector<int> answer(const vector<int> arr, int k)
{
vector<int> negatives;
vector<int> result;
int n = arr.size();
for (int i = 0; i < k; i++)
{
if (arr[i] < 0)
{
negatives.push_back(arr[i]);
}
}
for (int i = k; i < n; i++)
{
if (negatives.size() == 0)
{
result.push_back(0);
}
else
{
result.push_back(negatives.front());
}
if (arr[i] < 0)
{
negatives.push_back(arr[i]);
}
if (arr[i - k] < 0)
{
negatives.erase(negatives.begin());
}
}
return result;
}
// incorrect - doesn't take care of window without negative
vector<int> revision(const vector<int> arr, int k)
{
int n = arr.size();
vector<int> negatives;
vector<int> result;
for (int i = 0; i < n; i++)
{
if (arr[i] < 0)
{
negatives.push_back(arr[i]);
}
}
for (int i = 0; i < n - k + 1; i++)
{
result.push_back(negatives[i]);
}
return result;
}
// to correct implement we need to do first window in separate loop
vector<int> revision1(const vector<int> arr, int k)
{
int n = arr.size();
vector<int> negatives;
vector<int> result;
for (int i = 0; i < k; i++)
{
if (arr[i] < 0)
{
negatives.push_back(arr[i]);
}
}
for (int i = k; i < n; i++)
{
if (negatives.size() == 0)
{
result.push_back(0);
}
else
{
result.push_back(negatives.front());
}
if (arr[i] < 0)
{
negatives.push_back(arr[i]);
}
if (arr[i - k] < 0)
{
negatives.erase(negatives.begin());
}
}
return result;
}
// push_back, erase(pointer), begin()->iterator,end(), front()->value, back(), size(), empty()
// pop_back(), reverse(.begin(),.end()), sort(.begin(),.end());
// 2 vectors - neg and result, fill neg one loop for k; next loop- remove n.front() if i-k < 0, if neg.size()!=0; add to result;
//