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diff --git a/02_activities/assignments/Cohort_8/assignment1.sql b/02_activities/assignments/Cohort_8/assignment1.sql
index c992e3205..017053054 100644
--- a/02_activities/assignments/Cohort_8/assignment1.sql
+++ b/02_activities/assignments/Cohort_8/assignment1.sql
@@ -4,17 +4,24 @@
 
 --SELECT
 /* 1. Write a query that returns everything in the customer table. */
-
+SELECT *
+FROM customer;
 
 
 /* 2. Write a query that displays all of the columns and 10 rows from the cus- tomer table, 
 sorted by customer_last_name, then customer_first_ name. */
 
+SELECT *
+FROM customer
+ORDER BY customer_last_name, customer_first_name
+LIMIT 10;
 
 
 --WHERE
 /* 1. Write a query that returns all customer purchases of product IDs 4 and 9. */
-
+SELECT *
+FROM customer_purchases
+WHERE product_id IN (4, 9);
 
 
 /*2. Write a query that returns all customer purchases and a new calculated column 'price' (quantity * cost_to_customer_per_qty), 
@@ -22,11 +29,23 @@ filtered by customer IDs between 8 and 10 (inclusive) using either:
 	1.  two conditions using AND
 	2.  one condition using BETWEEN
 */
+
 -- option 1
 
+SELECT *,
+       quantity * cost_to_customer_per_qty AS price
+FROM customer_purchases
+WHERE customer_id >= 8
+  AND customer_id <= 10;
+
+
 
 -- option 2
 
+SELECT *,
+       quantity * cost_to_customer_per_qty AS price
+FROM customer_purchases
+WHERE customer_id BETWEEN 8 AND 10;
 
 
 --CASE
@@ -35,19 +54,46 @@ Using the product table, write a query that outputs the product_id and product_n
 columns and add a column called prod_qty_type_condensed that displays the word “unit” 
 if the product_qty_type is “unit,” and otherwise displays the word “bulk.” */
 
+SELECT
+    product_id,
+    product_name,
+    CASE
+        WHEN product_qty_type = 'unit' THEN 'unit'
+        ELSE 'bulk'
+    END AS prod_qty_type_condensed
+FROM product;
 
 
 /* 2. We want to flag all of the different types of pepper products that are sold at the market. 
 add a column to the previous query called pepper_flag that outputs a 1 if the product_name 
 contains the word “pepper” (regardless of capitalization), and otherwise outputs 0. */
 
-
+SELECT
+    product_id,
+    product_name,
+    CASE
+        WHEN product_qty_type = 'unit' THEN 'unit'
+        ELSE 'bulk'
+    END AS prod_qty_type_condensed,
+    CASE
+        WHEN LOWER(product_name) LIKE '%pepper%' THEN 1
+        ELSE 0
+    END AS pepper_flag
+FROM product;
 
 --JOIN
 /* 1. Write a query that INNER JOINs the vendor table to the vendor_booth_assignments table on the 
 vendor_id field they both have in common, and sorts the result by vendor_name, then market_date. */
 
-
+SELECT
+    v.*,
+    vba.*
+FROM vendor AS v
+INNER JOIN vendor_booth_assignments AS vba
+    ON v.vendor_id = vba.vendor_id
+ORDER BY
+    v.vendor_name,
+    vba.market_date;
 
 
 /* SECTION 3 */
@@ -56,7 +102,11 @@ vendor_id field they both have in common, and sorts the result by vendor_name, t
 /* 1. Write a query that determines how many times each vendor has rented a booth 
 at the farmer’s market by counting the vendor booth assignments per vendor_id. */
 
-
+SELECT 
+    vendor_id,
+    COUNT(*) AS times_rented
+FROM vendor_booth_assignments
+GROUP BY vendor_id;
 
 /* 2. The Farmer’s Market Customer Appreciation Committee wants to give a bumper 
 sticker to everyone who has ever spent more than $2000 at the market. Write a query that generates a list 
@@ -64,7 +114,23 @@ of customers for them to give stickers to, sorted by last name, then first name.
 
 HINT: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword. */
 
-
+SELECT 
+    c.customer_id,
+    c.customer_first_name,
+    c.customer_last_name,
+    SUM(cp.quantity * cp.cost_to_customer_per_qty) AS total_spent
+FROM customer AS c
+JOIN customer_purchases AS cp
+    ON c.customer_id = cp.customer_id
+GROUP BY 
+    c.customer_id,
+    c.customer_first_name,
+    c.customer_last_name
+HAVING 
+    total_spent > 2000
+ORDER BY 
+    c.customer_last_name,
+    c.customer_first_name;
 
 --Temp Table
 /* 1. Insert the original vendor table into a temp.new_vendor and then add a 10th vendor: 
@@ -78,6 +144,15 @@ When inserting the new vendor, you need to appropriately align the columns to be
 VALUES(col1,col2,col3,col4,col5) 
 */
 
+DROP TABLE IF EXISTS new_vendor;
+CREATE TEMPORARY TABLE new_vendor AS
+SELECT * FROM vendor;
+
+INSERT INTO new_vendor (vendor_id, vendor_name, vendor_type, vendor_owner_first_name, vendor_owner_last_name)
+VALUES (10, 'Thomas''s Superfood Store', 'Fresh Focused', 'Thomas', 'Rosenthal');
+
+
+SELECT * FROM new_vendor ORDER BY vendor_id;
 
 
 -- Date