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So this $\sH$ is not a RKHS. |
Might be worth clarifying that the set of square integrable continuous functions is not even a Hilbert space (since it's not complete, therefore immediately not an RKHS), but this non-example is illustrative. I can make a PR if helpful.
cs229t/lectures/notes.otl
Line 3680 in e5c8976
Might be worth clarifying that the set of square integrable continuous functions is not even a Hilbert space (since it's not complete, therefore immediately not an RKHS), but this non-example is illustrative. I can make a PR if helpful.